- ( The twins are triplets) In Figure 5, let
and
be the
points where the circle inscribed in the arbelos
is tangent to the two smaller semicircles,
and let
be the point where the two smaller
semicircles are tangent. The circle containing
,
and
has a radius equal to that of the
twin circles, namely
. See [ 8].
- ( Quadruplets) The largest circle inscribed
in the circular segment of the largest semi-
circle formed by the chord
tangent to
the other two semicircles also has the same
radius as the twins. See Figure 6. Note that the point of
tangency for this circle is the point
of the common internal tangent
to the smaller semicircles of the arbelos,
.
The story doesn't end here. There are infinite families of circles in and
around the arbelos with the same radius as the twins. See [ 10] and
[ 11].
- In Figure 7, a chain of circles, inscribed in two internally
tangent semicircles with collinear endpoints,
begins with a circle tangent to the line of
centers of the semicircles. The distance of
the center of the
th circle in the chain
from the line of centers is
where
is the radius of the
th circle.
- If the radius of the largest semicircle in an arbelos is
times
the radius
of the smallest semicircle, where
is an integer, then at least one pair
of circles
in the chain will have their centers on a line parallel to the base of the
arbelos. The
circles paired in this manner are those whose order numbers in the chain
have a product
equal to
. See On a Generalization of the Arbelos by M. G.
Gaba in the
American Mathematical Monthly, vol 47, Jan. 1940, pp 19-24.
- ( Valentine) Let
be the radii of the semicircles forming
an arbelos and let
be the radius of the inscribed circle. In Figure
8, prove
the ratio of the area of the arbelos to the area of the heart equals
.
See [ 9] for ten proofs by Charles W. Trigg.
See [ 4] for seven proofs that
.