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More inequalities

Cauchy(-Schwartz-Buniakowski) inequality:
If $ x_1,\dots,x_n,y_1,\dots,y_n$ are real numbers, then

$\displaystyle (x_1^2+\dots+x_n^2)(y_1^2+\dots+y_n^2)
\ge (x_1 y_1 + \dots + x_n y_n)^2.$


Chebychev's inequality:
If $ x_1 \ge \dots \ge x_n \ge 0$ and $ y_1 \ge \dots \ge y_n \ge 0$, then

$\displaystyle \frac{x_1 y_1 + \dots + x_n y_n}{n}
\ge
\left(\frac{x_1 + \dots + x_n}{n} \right)
\left(\frac{y_1 + \dots + y_n}{n} \right)$

with equality if and only if one of the sequences is constant.


Chebychev's inequality with three sequences:
If $ x_1 \ge \dots \ge x_n \ge 0$, $ y_1 \ge \dots \ge y_n \ge 0$, and $ z_1 \ge \dots \ge z_n \ge 0$, then

$\displaystyle \frac{x_1 y_1 z_1 + \dots + x_n y_n z_n}{n}
\ge
\left(\frac{x_1 +...
...t(\frac{y_1 + \dots + y_n}{n} \right)
\left(\frac{z_1 + \dots + z_n}{n} \right)$

with equality if and only if at least two of the three sequences are constant or one of the sequences is all zero.


You can probably guess what the four-sequence Chebychev inequality looks like.


Hölder's inequality:
Let $ a_1,\dots,a_n,b_1,\dots,b_n,\alpha,\beta>0$ and suppose that $ \alpha+\beta=1$. Then

$\displaystyle (a_1+\dots+a_n)^\alpha (b_1+\dots+b_n)^\beta
\ge (a_1^\alpha b_1^\beta + \dots + a_n^\alpha b_n^\beta),$

with equality if and only if

$\displaystyle \frac{a_1}{b_1} = \frac{a_2}{b_2} = \dots = \frac{a_n}{b_n}.$


Jensen's extension of Hölder's Inequality:
Suppose $ a_1,\dots,a_n,b_1,\dots,b_n,\dots,\ell_1,\dots,\ell_n,
\alpha,\beta,\dots,\lambda>0$, and $ \alpha+\beta+\dots+\lambda \ge 1$. Then

$\displaystyle \left(\sum_{i=1}^n a_i \right)^\alpha
\left(\sum_{i=1}^n b_i \rig...
...mbda
\ge
\sum_{i=1}^n
\left( a_i^\alpha b_i^\beta \dots \ell_i^\lambda \right).$


Rearrangement inequality:
Suppose $ a_1 \ge \dots \ge a_n$ and $ b_1 \ge \dots \ge b_n$ are real numbers. If $ \pi$ is a permutation of $ 1,2,\dots,n$, then

$\displaystyle a_1 b_n + a_2 b_{n-1} + \dots + a_n b_1
\le a_1 b_{\pi(1)} + \dots + a_n b_{\pi(n)}
\le a_1 b_1 + \dots + a_n b_n.$


Minkowski's inequality:
Suppose $ a_1,\dots,a_n,b_1,\dots,b_n \ge 0$, and $ r$ is a real number. If $ r>1$, then

$\displaystyle \sqrt[r]{a_1^r+\dots+a_n^r} + \sqrt[r]{b_1^r+\dots+b_n^r}
\ge \sqrt[r]{(a_1+b_1)^r+\dots+(a_n+b_n)^r}.$

If $ 0<r<1$, then the inequality is reversed.


Bernoulli's inequality:
If $ x>-1$ and $ 0<a<1$, then

$\displaystyle (1+x)^a \le 1+ax,$

with equality if and only if $ x=0$. The inequality reverses for $ a<0$ or $ a>1$.


next up previous
Next: Problems Up: Inequalities Previous: Symmetric function inequalities
Zvezdelina Stankova-Frenkel 2001-11-18