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The power mean inequality

Fix $ x_1,\dots,x_n \ge 0$. For $ r \not=0$ (assume $ r>0$ if some $ x_i$ are zero), the $ r$-th power mean $ P_r$ of $ x_1,\dots,x_n$ is defined to be the $ r$-th root of the average of the $ r$-th powers of $ x_1,\dots,x_n$:

$\displaystyle P_r := \left( \frac{x_1^r + \dots + x_n^r}{n} \right)^{1/r}.$

This formula yields nonsense if $ r=0$, but there is a natural way to define $ P_0$ too: it is simply defined to be the geometric mean1:

$\displaystyle P_0 := \sqrt[n]{x_1 x_2 \dots x_n}.$

One also defines

$\displaystyle P_\infty = \max\{x_1,\dots,x_n\}$

since when $ r$ is very large, $ P_r$ is a good approximation to the largest of $ x_1,\dots,x_n$. For a similar reason one uses the notation

$\displaystyle P_{-\infty}=\min\{x_1,\dots,x_n\}.$

Here are some examples:

$\displaystyle P_1 = \frac{x_1+\dots+x_n}{n}$

is the arithmetic mean,

$\displaystyle P_2 = \sqrt{\frac{x_1^2+\dots+x_n^2}{n}}$

is sometimes called the root mean square. For $ x_1,\dots,x_n>0$,

$\displaystyle P_{-1} = \frac{n}{\frac{1}{x_1} + \dots + \frac{1}{x_n}}$

is called the harmonic mean.


Power mean inequality:
Let $ x_1,\dots,x_n \ge 0$. Suppose $ r>s$ (and $ s \ge 0$ if any of the $ x_i$ are zero). Then $ P_r \ge P_s$, with equality if and only if $ x_1=x_2=\dots=x_n$.


The power mean inequality holds even if $ r=\infty$ or $ s=-\infty$, provided that we use the definitions of $ P_\infty$ and $ P_{-\infty}$ above, and the convention that $ \infty > r > -\infty$ for all numbers $ r$.

Here are some special cases of the power mean inequality:


next up previous
Next: Convex functions Up: Inequalities Previous: The AM-GM inequality
Zvezdelina Stankova-Frenkel 2001-11-18